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Equation Of The Tangent Line To The Curve At Given Point? Help?

By admin Posted in: Android

Find an equation of the tangent line to the curve at the given point.
1.) y equals 2x to the power 3 – 5x, (-1,3)
2.) y equals sqrt of x, ( 1,1)
Plz show work.had to spell out some symbols since there not on my Android key pad.

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  1. Tracy Says

    To find the slope, take the derivative of the function
    slope = y’ = 6x^2 – 5
    at point (-1,3), slope = y’(-1) = 6(-1)^2 – 5 = 1
    plug this information into point-slope form of a line
    (y-3) = (1)(x-(-1))
    y = x + 1 +3
    y = x+4
    For the second equation:
    slope = y’(1) = 1/(2sqrtx) = 1/2
    (y-1) = 1/2 (x-1)
    y = 1/2x + 1/2

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